First Bad Version
EASYDescription
You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.
Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.
You are given an API bool isBadVersion(version) which returns whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.
Example 1:
Input: n = 5, bad = 4 Output: 4 Explanation: call isBadVersion(3) -> false call isBadVersion(5) -> true call isBadVersion(4) -> true Then 4 is the first bad version.
Example 2:
Input: n = 1, bad = 1 Output: 1
Constraints:
1 <= bad <= n <= 231 - 1
Approaches
Checkout 2 different approaches to solve First Bad Version. Click on different approaches to view the approach and algorithm in detail.
Linear Search
Iterate through each version from 1 to n and check if it's a bad version using the isBadVersion API. Return the first bad version found.
Algorithm
- Start iterating from version 1 to n
- For each version, call isBadVersion(version)
- If isBadVersion returns true, return the current version
- If no bad version is found, return n
The linear search approach is the most straightforward solution. We start checking each version from 1 up to n using the isBadVersion API. As soon as we find a bad version, we return it since it will be the first bad version (as all versions after a bad version are also bad).
public class Solution extends VersionControl {
public int firstBadVersion(int n) {
for (int version = 1; version <= n; version++) {
if (isBadVersion(version)) {
return version;
}
}
return n;
}
}
In this approach, we simply use a for loop to check each version. When we find the first bad version, we return it immediately.
Complexity Analysis
Pros and Cons
- Simple and easy to understand
- Works for small inputs
- Minimal space requirement
- Inefficient for large inputs
- Makes too many API calls
- Does not minimize the number of calls to the API as required
Code Solutions
Checking out 4 solutions in different languages for First Bad Version. Click on different languages to view the code.
/* The isBadVersion API is defined in the parent class VersionControl. boolean isBadVersion(int version); */ public class Solution extends VersionControl { public int firstBadVersion ( int n ) { int left = 1 , right = n ; while ( left < right ) { int mid = ( left + right ) >>> 1 ; if ( isBadVersion ( mid )) { right = mid ; } else { left = mid + 1 ; } } return left ; } }Video Solution
Watch the video walkthrough for First Bad Version
Similar Questions
5 related questions you might find useful
Algorithms:
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